-
Title: Generalized Eigenspaces
-
Series: Abstract Linear Algebra
-
Chapter: Some matrix decompositions
-
YouTube-Title: Abstract Linear Algebra 36 | Generalized Eigenspaces
-
Bright video: Watch on YouTube
-
Dark video: Watch on YouTube
-
Ad-free video: Watch Vimeo video
-
Original video for YT-Members (bright): Watch on YouTube
-
Original video for YT-Members (dark): Watch on YouTube
-
Forum: Ask a question in Mattermost
-
Quiz: Test your knowledge
-
Dark-PDF: Download PDF version of the dark video
-
Print-PDF: Download printable PDF version
-
Thumbnail (bright): Download PNG
-
Thumbnail (dark): Download PNG
-
Subtitle on GitHub: ala36_sub_eng.srt missing
-
Download bright video: Link on Vimeo
-
Download dark video: Link on Vimeo
-
Timestamps (n/a)
-
Subtitle in English (n/a)
-
Quiz Content
Q1: Let $A \in \mathbb{C}^{n \times n}$ for $n\geq 2$ and $\lambda = 0$ be an eigenvalue. What is always correct?
A1: There is a generalized eigenvector of rank $1$.
A2: There is a generalized eigenvector of rank $2$.
A3: There is a generalized eigenvector of rank $n$.
A4: There are no generalized eigenvectors of rank $n$.
Q2: Let $A \in \mathbb{C}^{n \times n}$ and $\lambda = 0$ be an eigenvalue. Assume that $x$ is a generalized eigenvector of rank $2$. What is correct?
A1: $Ax$ is an ordinary eigenvector for the eigenvalue $\lambda = 0$.
A2: $x$ is also an ordinary eigenvector for the eigenvalue $\lambda = 0$.
A3: $Ax = 0$.
A4: $\mathrm{Ker}(A^2) = { 0 }$.
Q3: Let $A = \begin{pmatrix} 0 & 1 \ 0 & 0\end{pmatrix}$. What is correct?
A1: $\mathrm{Ker}(A^2) = { 0 }$.
A2: $\mathrm{Ker}(A^2) = \mathbb{C}^2 $.
A3: $\mathrm{Ker}(A^2) = \mathbb{C}$.
A4: $\mathrm{Ker}(A)$ is two-dimensional.
A5: $\mathrm{Ker}(A) = { 0 }$.
-
Date of video: 2024-11-28
-
Last update: 2026-03