• Title: Weak Law of Large Numbers

  • Series: Probability Theory

  • Chapter: Convergence of Random Variables

  • YouTube-Title: Probability Theory 28 | Weak Law of Large Numbers

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  • Quiz Content

    Q1: What does it mean that a family of random variables is i.i.d?

    A1: It means that they are independent and identically distributed.

    A2: It means that they are independent and identically defined.

    A3: It means that they are identically distributed and intelligent.

    A4: It means that they are intrinsically independent distributed.

    Q2: Let $X_k: \Omega \rightarrow \mathbb{R}$ be a random variable where $\mathbb{E}(|X_1|)$ exists. What is the correct statement for the weak law of large numbers?

    A1: If $(X_k){k \in \mathbb{N}}$ are i.i.d., then \newline $ \displaystyle \mathbb{P}\left( \Big| \frac{1}{n} \sum{k = 1}^n X_k - \mathbb{E}(X_1) \Big| \geq \varepsilon \right) $ $ \displaystyle \xrightarrow{n \rightarrow \infty} 0 $

    A2: If $(X_k){k \in \mathbb{N}}$ are i.i.d., then $ \displaystyle\mathbb{P}\left( \Big| \frac{1}{n} \sum{k = 1}^n X_k - \mathbb{E}(X_1) \Big| = \varepsilon \right) $ $ \displaystyle \xrightarrow{n \rightarrow \infty} 0 $

    A3: If $(X_k){k \in \mathbb{N}}$ are i.i.d., then $ \displaystyle \mathbb{P}\left( \Big| \frac{1}{n} \sum{k = 1}^n X_k - \mathbb{E}(X_1) \Big| \leq \varepsilon \right) $ $ \displaystyle \xrightarrow{n \rightarrow \infty} 0 $

    A4: If $(X_k){k \in \mathbb{N}}$ are i.i.d., then $ \displaystyle \mathbb{P}\left( \Big| \frac{1}{n} \sum{k = 1}^n X_k - \mathbb{E}(X_1) \Big| \leq \varepsilon \right) $ $ \displaystyle \xrightarrow{n \rightarrow \infty} \frac{1}{\varepsilon} $

  • Last update: 2025-09

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